In a.c. circuit, a resistance $R=40 \Omega$ and an inductance ' $L$ ' are connected in series. If the phase…

In a.c. circuit, a resistance $R=40 \Omega$ and an inductance ' $L$ ' are connected in series. If the phase angle between voltage and current is $45^{\circ}$, then the value of the inductive reactance is $\left(\tan 45^{\circ}=1\right)$
  1. $50 \Omega$
  2. $40 \Omega$
  3. $10 \Omega$
  4. $20 \Omega$

Solution

$\begin{aligned} & \tan \phi=\tan 45^{\circ}=\frac{\mathrm{X}_{\mathrm{L}}}{\mathrm{R}} \\ & \mathrm{X}_{\mathrm{I}}=\mathrm{R}=40 \Omega\end{aligned}$

Asked in: MHT CET 2021 (22 Sep Shift 1)

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