In Δ A B C ,   r 1 - r a + r 2 - r b + r 3 - r c =

In ΔABC, r1-ra+r2-rb+r3-rc=
  1. r1+r2+r3s
  2. r1+r2+r32s
  3. r1+r2+r32
  4. r1+r2+r33s

Solution

We have, r1-ra+r2-rb+r3-rc

⇒1a∆s-a-∆s+1b∆s-b-∆s+1c∆s-c-∆s

=∆ss-a+∆ss-b+∆ss-c

=r1s+r2s+r3s

=r1+r2+r3s

Asked in: AP EAMCET 2018 (25 Apr Shift 1)

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