In a zero order reaction for every $10^{\circ}$ rise of temperature, the rate is doubled. If the temperature…
In a zero order reaction for every $10^{\circ}$ rise of temperature, the rate is doubled. If the temperature is increased from $10^{\circ} \mathrm{C}$ to $100^{\circ} \mathrm{C}$, the rate of the reaction will become
256 times
512 times
64 times
128 times
Solution
For $10^{\circ}$ rise in temperature, $n=1$ so rate $=2^n=2^1=2$
When temperature is increased from $10^{\circ} \mathrm{C}$ to $100^{\circ} \mathrm{C}$, change in temperature $=100-10=90^{\circ} \mathrm{C}$, i.e., $n=9$
So, rate $=2^9=512$ times
Alternate method With every $10^{\circ}$ rise in temperature, rate becomes double, so $\frac{r^{\prime}}{r}=2^{\left(\frac{100-10}{10}\right)}=2^9=512$ times.