In a Young's double slit experiment, if the wavelength of light is increased by $50 \%$ and the distance…

In a Young's double slit experiment, if the wavelength of light is increased by $50 \%$ and the distance between the slits is doubled then the percentage change in fringe width is
  1. $75$
  2. $50$
  3. $25$
  4. $15$

Solution

Wavelength of light, $\lambda^{\prime}=50 \lambda$ Distance between the slit, $\mathrm{d}^{\prime}=2 \mathrm{~d}$ fringe width, $\beta^{\prime}=\frac{D \lambda^{\prime}}{d^{\prime}}$ $\begin{aligned} & =\frac{D \times 0.50 \lambda}{2 d}=0.25 \beta \\ & \left|\frac{\beta^{\prime}-\beta}{\beta}\right| \times 100 \%=|0.25-1| \times 100 \% \\ & =75 \% . \end{aligned}$

Asked in: AP EAMCET 2023 (15 May Shift 2)

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