In a Wheatstone's bridge all the four arms have equal resistance $R$. If the resistance of the galvanometer…
In a Wheatstone's bridge all the four arms have equal resistance $R$. If the resistance of the galvanometer arm is also $R$, the equivalent resistance of the combination as seen by the battery is:
$\frac{R}{4}$
$\frac{R}{2}$
$R$
$2 R$
Solution
Resistance seen by the battery $=$ Equivalent resistance between $A$ and $B$ is $R$.
Resistance seen by the battery $=$ Equivalent resistance between $A$ and $B$ is $R$.