In a uniformly charged sphere of total charge $Q$ and radius $R$, the electric field $E$ is plotted as a function of distance from the centre. The graph which would correspond to the above will be

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Aicharya · Accepted Answer

$\overrightarrow{\mathrm{E}}_{	ext {inside }}=\left(\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{Q}}{\mathrm{R}^3}ight) \overrightarrow{\mathrm{r}}$ $\overrightarrow{\mathrm{E}}_{	ext {outside }}\left(\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{Q}}{\mathrm{r}^3}ight) \overrightarrow{\mathrm{r}}$ $	herefore$

In a uniformly charged sphere of total charge $Q$ and radius $R$, the electric field $E$ is plotted as a…

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