In a two-digit number, sum of digits is $9$. If digits are reversed, the new number is $27$ less than the original. Original number is

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Aicharya · Accepted Answer

Tens digit $a$, units $b$. $a+b=9, 10a+b - (10b+a) = 27 \Rightarrow 9(a-b) = 27 \Rightarrow a-b=3$. So $a=6, b=3$. Number $= 63$.

In a two-digit number, sum of digits is $9$. If digits are reversed, the new number is $27$ less than the…