In a triangle ABC , if $\mathrm{BC}=5, \mathrm{CA}=6, \mathrm{AB}=7$, then the length of the median drawn…
- 5
- $7 \sqrt{5}$
- $7 \sqrt{2}$
- $2 \sqrt{7}$
Solution
Median from B onto $\mathrm{AC}=\sqrt{\frac{2 a^2+2 c^2-b^2}{4}}$ $=\sqrt{\frac{2 \times 25+2 \times 49-36}{4}}=2 \sqrt{7}$
Asked in: AP EAMCET 2024 (21 May Shift 1)