In a travelling wave $y = 0.1 \sin \pi \left(x - 330 t + \frac{2}{3}\right)$ (SI units) The phase difference…

In a travelling wave $y = 0.1 \sin \pi \left(x - 330 t + \frac{2}{3}\right)$ (SI units) The phase difference between $x_1 = 3\text{ m}$ and $x_2 = 3.5\text{ m}$ is
  1. $\frac{\pi}{2}$
  2. $\pi$
  3. $\frac{3\pi}{2}$
  4. $2\pi$

Solution

Phase difference, $\Delta \phi = k \cdot \Delta x$ $\Rightarrow \Delta \phi = \frac{2\pi}{\lambda} \times \Delta x = \pi \times (3.5 - 3) = \frac{\pi}{2} \left(\because k = \frac{2\pi}{\lambda} = \pi\right)$

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