In a trapezium $PQRS$ with $PQ \parallel SR$, $\angle P + \angle S$ equals
In a trapezium $PQRS$ with $PQ \parallel SR$, $\angle P + \angle S$ equals
- $180^{\circ}$
- $90^{\circ}$
- $60^{\circ}$
- $360^{\circ}$
Solution
Co-interior on parallel sides.
Asked in: MH-SSC-9
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