In a transformer, number of turns in the primary coil are 140 and that in the secondary coil are 280. If…

In a transformer, number of turns in the primary coil are 140 and that in the secondary coil are 280. If current in primary coil is $4 \mathrm{~A}$, then that in the secondary coil is
  1. 4 A
  2. 2 A
  3. 6 A
  4. 10 A

Solution

$I_1 N_1=I_2 N_2 \Rightarrow I_2=\frac{4 \times 140}{280}=2 \mathrm{~A}$

Asked in: JEE Main 2002

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