In a $\triangle A B C,(a+b+c)(b+c-a)=\lambda b c$, then
In a $\triangle A B C,(a+b+c)(b+c-a)=\lambda b c$, then
- $\lambda < -6$
- $\lambda>6$
- $0 < \lambda < 4$
- $\lambda>4$
Solution
No solution. Refer to answer key.
Asked in: AP EAMCET 2015
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