In a spring gun having spring constant 100   N   m - 1 a small ball B of mass 100   g is put…

In a spring gun having spring constant 100 N m-1 a small ball B of mass 100 g is put in its barrel (as shown in figure) by compressing the spring through 0.05 m. There should be a box placed at a distance d on the ground so that the ball falls in it. If the ball leaves the gun horizontally at a height of 2 m above the ground. The value of d is m.
g=10 m s-2

Solution

12kx2=12mv2
Kx2=mv2
v=xkm=0.051000.1=0.05×1010
v=0.510
From h=12gt2
t=2 h g=2×210=210
 d=vt=0.510×210=1 m

Asked in: JEE Main 2021 (20 Jul Shift 1)

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