In a sports competition, a javelin in thrown at an angle $45^{\circ}$, which recorded a range of $90…

In a sports competition, a javelin in thrown at an angle $45^{\circ}$, which recorded a range of $90 \mathrm{~m}$. The maximum height reached by the javelin is (Neglect air resistance and acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )
  1. $45 \mathrm{~m}$
  2. $30 \mathrm{~m}$
  3. $22.5 \mathrm{~m}$
  4. $30 \sqrt{2} \mathrm{~m}$

Solution

$\mathrm{R}=\frac{\mathrm{H}}{4} \tan \theta=\frac{90}{4} \tan 45^{\circ}=22.5 \mathrm{~m}$

Asked in: AP EAMCET 2022 (06 Jul Shift 1)

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