In a set of reactions, ethyl benzene yielded a product $D$. ' $D$ ' would be

In a set of reactions, ethyl benzene yielded a product $D$. ' $D$ ' would be

Solution

Key Idea Alkaline $\mathrm{KMnO}_4$ converts complete carbon chain that is directly attached to benzene nucleus, to $-\mathrm{COOH}$ group. $\mathrm{Br}_2$ in the presence of halogon carrier causes bromination and ethyl alcohol in acidic medium results in esterification.

Asked in: NEET 2010 (Screening)

Practice more Carboxylic Acid Derivatives questions on Aicharya