In a Rutherford scattering experiment when a projectile of charge $Z_1$ and mass $M_1$ approaches a target…

In a Rutherford scattering experiment when a projectile of charge $Z_1$ and mass $M_1$ approaches a target nucleus of charge $Z_2$ and mass $M_2$, the distance of closest approach is $r_0$. The energy of the projectile is :
  1. Directly proportional to mass $M_1$
  2. Directly proportional to $\mathrm{M}_1 \times \mathrm{M}_2$
  3. Directly proportional to $Z_1 Z_2$
  4. Inversely proportional to $Z_1$

Solution

$\text {Energy }=\frac{1}{4 \pi \in_0} \frac{Z_1 Z_2}{\mathrm{r}_0}$

Asked in: NEET 2009 (Mains)

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