In a resonance column, two successive resonances are obtained at depths $30\text{ cm}$ and $50\text{ cm}$,…

In a resonance column, two successive resonances are obtained at depths $30\text{ cm}$ and $50\text{ cm}$, respectively. The next resonance will be obtained at a depth
  1. 60 cm
  2. 80 cm
  3. 70 cm
  4. 90 cm

Solution

Here, $\frac{\lambda}{2} = (50 - 30)\text{ cm} = 20\text{ cm}$ Next resonance will be obtained at $50 + \frac{\lambda}{2} = 70\text{ cm}$

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