In a regular octahedral molecule, $\mathrm{MX}_{6}$ the number of $X-M-X$ bonds at $180^{\circ}$ is

In a regular octahedral molecule, $\mathrm{MX}_{6}$ the number of $X-M-X$ bonds at $180^{\circ}$ is
  1. three
  2. two
  3. $\mathrm{six}$
  4. four

Solution



Thus here bond angles between
$\mathrm{X}_{4}-\mathrm{M}-\mathrm{X}_{2}=180^{\circ}$
$\mathrm{X}_{1}-\mathrm{M}-\mathrm{X}_{3}=180^{\circ}$
$\mathrm{X}_{5}-\mathrm{M}-\mathrm{X}_{6}=180^{\circ}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

Practice more CHEMICAL BONDING AND MOLECULAR STRUCTURE questions on Aicharya