In a reactor, 2   kg of U 235 92 fuel is fully used up in 30 days. The energy released fission is 200…

In a reactor, 2 kg of U23592 fuel is fully used up in 30 days. The energy released fission is 200 MeV. Given that the Avogadro number, N=6.023×1026 per kilo mole and 1 eV=1.6×10-19 J. The power output of the reactor is close to:
  1. 35 MW
  2. 60 MW
  3. 125 MW
  4. 54 MW

Solution

P=Et

=2235×6.023×1026×200×1.6×10-1930×24×60×60=60 MW

Asked in: JEE Main 2020 (02 Sep Shift 1)

Practice more Work Power Energy questions on Aicharya