In a reaction the ferrous $\left(\mathrm{Fe}^{+2}ight)$ ion is oxidised to ferric…

In a reaction the ferrous $\left(\mathrm{Fe}^{+2}ight)$ ion is oxidised to ferric $\left(\mathrm{Fe}^{+3}ight)$ ion. The equivalent weight of the ion in the above reaction is equal to
  1. Half of the atomic weight
  2. $1 / 5$ of the atomic weight
  3. The atomic veight
  4. Twice the atomic weight

Solution

The atomic weight :
Equivalent weight $=\frac{\text { Atomic weight }}{\text { No. of e lost or gained }}$
$\mathrm{Fe}^{2+} \longrightarrow \mathrm{Fe}^{3+}+\mathrm{e}^{-}$
$\therefore$ Equivalent weight $=$ Atomic weight undefined

Asked in: JEE-TOPICTESTS-CHEMISTRY

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