In a random experiment, two dice are thrown and the sum of the numbers appeared on them is recorded. This…

In a random experiment, two dice are thrown and the sum of the numbers appeared on them is recorded. This experiment is repeated 9 times. If the probability that a sum of 6 appears at least once is $\mathrm{P}_1$ and a sum of 8 appears at least once is $\mathrm{P}_2$, then $\mathrm{P}_1: \mathrm{P}_2=$
  1. $4: 3$
  2. $3: 1$
  3. $1: 2$
  4. $1: 1$

Solution

$P_1=\left(\frac{6}{36}\right)^9, P_2=\left(\frac{6}{36}\right)^9 \quad \therefore P_1: P_2=1: 1$

Asked in: AP EAMCET 2024 (20 May Shift 1)

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