In a potentiometer arrangement, a cell gives a balancing point at 75   cm length of wire. This cell is now replaced by another cell of unknown emf. If the ratio of the emf's of two cells respectively is 3 : 2 , the difference in the balancing length of the potentiometer wire in above two…

Question

In a potentiometer arrangement, a cell gives a balancing point at 75 &#160; cm length of wire. This cell is now replaced by another cell of unknown emf. If the ratio of the emf's of two cells respectively is 3 : 2 , the difference in the balancing length of the potentiometer wire in above two cases will be _____ cm .

Aicharya · Accepted Answer

If the potential difference between the potentiometer is $V$ and the potential of the battery is $ε$ .

Then, $\frac{ε}{V} = \frac{l}{L}$

Therefore, $\frac{ε_{1}}{ε_{2}} = \frac{l_{1}}{l_{2}} \Rightarrow \frac{3}{2} = \frac{75}{x} \Rightarrow x = 50 cm$

Therefore, the difference in the balancing length is $75 - 50 = 25 cm$

In a potentiometer arrangement, a cell gives a balancing point at 75   cm length of wire. This cell is…

Solution

In a potentiometer arrangement, a cell gives a balancing point at 75 &#160; cm length of wire. This cell is…

Solution

In a potentiometer arrangement, a cell gives a balancing point at 75 cm length of wire. This cell is…