In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa, and the remaining 160 to aa, Based…

According to Hardy$–$Weinberg principle: 
Frequency of dominant allele (A) = p                      
Frequency of recessive allele (a) = q 
Frequency of AA individuals = p × p = p²                  
Frequency of aa individuals = q × q = q²
Frequency of Aa individuals = 2pq                         
Total population = 1000
Frequency of AA individuals = p × p = p² = 360/1000 = 0.36                  
Frequency of dominant allele (A) = p = 0.6