In a plot of \(\log \left(\frac{x}{m}\right) v s \log p\), for the adsorption of a gas on solid, a straight…
In a plot of \(\log \left(\frac{x}{m}\right) v s \log p\), for the adsorption of a gas on solid, a straight line is obtained. The slope of that straight line is
\(\frac{1}{n}\)
\(K\)
\(n\)
\(\log K\)
Solution
From Freundlich adsorption isotherm, \(\frac{x}{m}=K p^{\frac{1}{n}}\) \(\Rightarrow \log \frac{x}{m}=\log K+\frac{1}{n} \log p\)
So, the plot of \(\log \left(\frac{x}{m}\right)\) ws \(\log p\) results a straight line of slope \(=\frac{1}{n}\) intercept \(=\log K\)
