In a photoelectric effect experiment, the threshold wavelength of light is $380 n m$ . If the wavelength of incident light is $260 n m$ , the maximum kinetic energy of emitted electrons will be
Given $E$ (in $e V$ ) $= \frac{1237}{λ (i n n m)}$

Question

In a photoelectric effect experiment, the threshold wavelength of light is

380 n m

. If the wavelength of incident light is

260 n m

, the maximum kinetic energy of emitted electrons will be
Given

E

(in

e V

)

= \frac{1237}{λ (i n n m)}

Aicharya · Accepted Answer

From Einstein’s photoelectric equation, K . E m a x = h c λ - h c λ 0 (here, λ 0 = threshold wavelength) = 1237 260 - 1237 380 = 1237 380 - 260 380 × 260 = 1.5 e V

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