In a parallel plate capacitor, the capacitance increases from \(6 \mu \mathrm{F}\) to \(60 \mu \mathrm{F}\)…
In a parallel plate capacitor, the capacitance increases from \(6 \mu \mathrm{F}\) to \(60 \mu \mathrm{F}\) on introducing a dielectric medium between the plates. The dielectric constant of the medium is
Solution
After introducing the dielectric medium, the capacitance of the capacitor is \(C^{\prime}=\mathrm{kC}\) (Where \(\mathrm{C}\) is the capacitance of the air-filled capacitor)
$\begin{aligned}
60 \mu F &= k(6 \mu F) \\
\Rightarrow k &= \frac{60 \mu F}{6 \mu F} \\
&=10
\end{aligned}$