In a parallel plate capacitor, the capacitance increases from \(6 \mu \mathrm{F}\) to \(60 \mu \mathrm{F}\)…

In a parallel plate capacitor, the capacitance increases from \(6 \mu \mathrm{F}\) to \(60 \mu \mathrm{F}\) on introducing a dielectric medium between the plates. The dielectric constant of the medium is

Solution

After introducing the dielectric medium, the capacitance of the capacitor is \(C^{\prime}=\mathrm{kC}\) (Where \(\mathrm{C}\) is the capacitance of the air-filled capacitor)
$\begin{aligned} 60 \mu F &= k(6 \mu F) \\ \Rightarrow k &= \frac{60 \mu F}{6 \mu F} \\ &=10 \end{aligned}$

Asked in: JEE Mains - Capacitance - Chapter Test

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