In a parallel-plate capacitor of capacitance $C$, a metal sheet is inserted between the plates parallel to them. The thickness of the sheet is half of the separation between the plate The capacitance now becomes

Question

Aicharya · Accepted Answer

Before the metal sheet is inserted, $C=\frac{\varepsilon_{0} A}{d}$
After the sheet is inserted, the system is equivalent to two capacitors in series, each of
capacitance $C=\frac{\varepsilon_{0} A}{(d / 4)}=4 C .$
The equivalent capacity is now $2 C$.

In a parallel-plate capacitor of capacitance $C$, a metal sheet is inserted between the plates parallel to…

Solution