In a nuclear reactor, the fuel is consumed at the rate of $1 \times 10^{-3} \mathrm{gs}^{-1}$. The power…
In a nuclear reactor, the fuel is consumed at the rate of $1 \times 10^{-3} \mathrm{gs}^{-1}$. The power generated in kW is
- $9 \times 10^{14}$
- $9 \times 10^7$
- $9 \times 10^8$
- $9 \times 10^{12}$
Solution
In nuclear reactor
$\begin{aligned} & \frac{\Delta \mathrm{m}}{\Delta \mathrm{t}}=1 \times 10^{-3} \mathrm{~g} \mathrm{~s}^{-1}=10^{-6} \mathrm{~kg} \mathrm{~s}^{-1} \\ & \begin{aligned} \therefore \text { Power }=\frac{\Delta \mathrm{E}}{\Delta \mathrm{t}}\left(\frac{\Delta \mathrm{m}}{\Delta \mathrm{t}}\right) \mathrm{c}^2= & 10^{-6} \times\left(3 \times 10^8\right)^2 \\ = & 9 \times 10^7 \mathrm{~kW}\end{aligned}\end{aligned}$
Asked in: AP EAMCET 2024 (23 May Shift 1)
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