In a nuclear fission process, a high mass nuclide ( A ≈ 236 ) with binding energy 7 . 6 MeV / Nucleon dissociated into two middle mass nuclides ( A ≈ 118 ) , having binding energy of 8 . 6 MeV / Nucleon. The energy released in the process would be _______ MeV .

Question

Aicharya · Accepted Answer

The formula to calculate the energy released in the given process can be written as

$Q = B E_{Product} - B E_{Reactant} . . . (1)$

From equation (1), it follows that

$\begin{array}{rcl} Q & = & 2 (118) (8.6) - 236 (7.6) MeV \\ = & 236 MeV \end{array}$

In a nuclear fission process, a high mass nuclide ( A ≈ 236 ) with binding energy 7 . 6 MeV / Nucleon…

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