In a multielectron atom, which of the following orbitals described by three quantum numbers will have same…

In a multielectron atom, which of the following orbitals described by three quantum numbers will have same energy in absence of electric and magnetic fields?
A. $\mathrm{n}=1, \mathrm{l}=0, \mathrm{~m}_1=0$
B. $\mathrm{n}=2, \mathrm{l}=0, \mathrm{~m}_1=0$
C. $\mathrm{n}=2, \mathrm{l}=1, \mathrm{~m}_1=1$
D. $\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_1=1$
E. $\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_1=0$
Choose the correct answer from the options given below:
  1. B and C Only
  2. A and B Only
  3. C and D Only
  4. D and E Only

Solution

$\begin{array}{lc} & \text { orbital } \\ \mathrm{A}: \mathrm{n}=1, \ell=0, \mathrm{~m}_{\ell}=0 & 1 \mathrm{~s} \\ \mathrm{B}: \mathrm{n}=2, \ell=0, \mathrm{~m}_{\ell}=0 & 2 \mathrm{~s} \\ \mathrm{C}: \mathrm{n}=3, \ell=1, \mathrm{~m}_{\ell}=1 & 3 \mathrm{p} \\ \mathrm{D}: \mathrm{n}=3, \ell=2, \mathrm{~m}_{\ell}=1 & 3 \mathrm{~d} \\ \mathrm{E}: \mathrm{n}=3, \ell=2, \mathrm{~m}_{\ell}=0 & 3 \mathrm{~d} \\ \end{array}$
In absence of electric and magnetic fields, all orbitals of 3d are degenerate

Asked in: JEE Main 2025 (28 Jan Shift 1)

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