In a multielectron atom, which of the following orbitals described by three quantum numbers will have same…
In a multielectron atom, which of the following orbitals described by three quantum numbers will have same energy in absence of electric and magnetic fields? A. $\mathrm{n}=1, \mathrm{l}=0, \mathrm{~m}_1=0$ B. $\mathrm{n}=2, \mathrm{l}=0, \mathrm{~m}_1=0$ C. $\mathrm{n}=2, \mathrm{l}=1, \mathrm{~m}_1=1$ D. $\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_1=1$ E. $\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_1=0$ Choose the correct answer from the options given below:
B and C Only
A and B Only
C and D Only
D and E Only
Solution
$\begin{array}{lc} & \text { orbital } \\ \mathrm{A}: \mathrm{n}=1, \ell=0, \mathrm{~m}_{\ell}=0 & 1 \mathrm{~s} \\ \mathrm{B}: \mathrm{n}=2, \ell=0, \mathrm{~m}_{\ell}=0 & 2 \mathrm{~s} \\ \mathrm{C}: \mathrm{n}=3, \ell=1, \mathrm{~m}_{\ell}=1 & 3 \mathrm{p} \\ \mathrm{D}: \mathrm{n}=3, \ell=2, \mathrm{~m}_{\ell}=1 & 3 \mathrm{~d} \\ \mathrm{E}: \mathrm{n}=3, \ell=2, \mathrm{~m}_{\ell}=0 & 3 \mathrm{~d} \\ \end{array}$ In absence of electric and magnetic fields, all orbitals of 3d are degenerate