In a metre bridge experiment, the ratio of the left gap resistance to right gap resistance is $2: 3$, the…
In a metre bridge experiment, the ratio of the left gap resistance to right gap resistance is $2: 3$, the balance point from left is
- $60 \mathrm{~cm}$
- $50 \mathrm{~cm}$
- $40 \mathrm{~cm}$
- $20 \mathrm{~cm}$
Solution
Here, $\frac{P}{Q}=\frac{2}{3}$
We know
$\begin{aligned} \frac{P}{Q} & =\frac{l}{100-l} \\ \Rightarrow \quad \frac{2}{3} & =\frac{l}{100-l} \\ \Rightarrow \quad l & =40 \mathrm{~cm}\end{aligned}$
Asked in: AP EAMCET 2007
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