In a $\triangle A B C$, let $\angle C=\frac{\pi}{2}$. If $r$ and $R$ are respectively inradius and…

In a $\triangle A B C$, let $\angle C=\frac{\pi}{2}$. If $r$ and $R$ are respectively inradius and circumradius of $A B C$, then $R+r=$
  1. $\frac{a-b}{2}$
  2. $\frac{a+b}{2}$
  3. $a+b$
  4. $a-b$

Solution


$ x+y=2 R $ Now, $ \begin{array}{ll} & a+b=x+r+y+r=2 R+2 r \\ \therefore & R+r=\frac{a+b}{2} \end{array} $

Asked in: AP EAMCET 2022 (07 Jul Shift 2)

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