In a hydrogen like atom, when an electron jumps from the M-shell to the L-shell, the wavelength of emitted…

In a hydrogen like atom, when an electron jumps from the M-shell to the L-shell, the wavelength of emitted radiation is $L$. If an electron jumps from $\mathrm{N}$ -shell to the $\mathrm{L}$ -shell, the wavelength of emitted radiation will be:
  1. $\frac{27}{20} \lambda$
  2. $\frac{16}{25} \lambda$
  3. $\frac{25}{16} \lambda$
  4. $\frac{20}{27} \lambda$

Solution

When electron jumps from $\mathrm{M} \rightarrow \mathrm{L}$ shell $\frac{1}{\lambda}=\mathrm{K}\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)=\frac{\mathrm{K} \times 5}{36}$ When eletron jumps from $\mathrm{N} \rightarrow \mathrm{L}$ shell $\frac{1}{\lambda^{\prime}}=K\left(\frac{1}{2^{2}}-\frac{1}{4^{2}}\right)=\frac{K \times 3}{16}$ solving equation (i) and (ii) we get $\lambda^{\prime}=\frac{20}{27} \lambda$

Asked in: JEE Main 2019 (11 Jan Shift 2)

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