In a hydrogen atom, if energy of an electron $1 n$ ground state is $13.6 . \mathrm{ev}$, then that in the…
- $1.51 \mathrm{eV}$
- $3.4 \mathrm{eV}$
- $6.04 \mathrm{eV}$
- $13.6 \mathrm{eV}$.
Solution
$\mathrm{E}_{\mathrm{n}}=\frac{13.6}{\mathrm{n}^{2}} \mathrm{eV}$ or $\mathrm{E}=\frac{13.6}{9} \mathrm{eV}=1.51 \mathrm{eV}$
Asked in: JEE-TOPICTESTS-CHEMISTRY