In a hydrogen atom, if energy of an electron $1 n$ ground state is $13.6 . \mathrm{ev}$, then that in the…

In a hydrogen atom, if energy of an electron $1 n$ ground state is $13.6 . \mathrm{ev}$, then that in the $2^{\text {nd }}$ excited state is
  1. $1.51 \mathrm{eV}$
  2. $3.4 \mathrm{eV}$
  3. $6.04 \mathrm{eV}$
  4. $13.6 \mathrm{eV}$.

Solution

$2^{\text {nd }}$ excited state will be the $3^{\text {rd }}$ energy level
$\mathrm{E}_{\mathrm{n}}=\frac{13.6}{\mathrm{n}^{2}} \mathrm{eV}$ or $\mathrm{E}=\frac{13.6}{9} \mathrm{eV}=1.51 \mathrm{eV}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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