In a hollow spherical shell, potential (V) changes with respect to distance (s) from centre as

Question

Aicharya · Accepted Answer

In shell, q charge is uniformly distributed over its surface, it behaves as a conductor.

\(V=\) potential at surface \(=\frac{q}{4 \pi \varepsilon_0 R}\) and inside \(V=\frac{q}{4 \pi \varepsilon_0 R}\)
Because of this it behaves as an equipotential surface.
Outside the shell \(V=\frac{q}{4 \pi \varepsilon_0 \mathrm{r}}, r\) is the distance from the centre.
Option 2 will best representation.

In a hollow spherical shell, potential (V) changes with respect to distance (s) from centre as

Solution