
In a given network the equivalent capacitance between $A$ and $B$ is $\left[C_{1}=C_{4}=1 \mu \mathrm{F},…

- $3 \mu F$
- $6 \mu F$
- $4.5 \mu F$
- $2.5 \mu F$
Solution

In a given network the equivalent capacitance between \(A\) and \(B\) is
\(\left[C_1=C_4=1 \mu F, C_2=C_3=2 \mu F\right]\)
\(C_{\text {eq }}=3 \mu \mathrm{F}\)
Asked in: JEE Mains - Capacitance - Test 1