In a given meter bridge, the current flowing through $40 \Omega$ resistor is

In a given meter bridge, the current flowing through $40 \Omega$ resistor is
  1. $\mathrm{I}_2+\mathrm{I}_{\mathrm{g}}$
  2. $\mathrm{I}_{\mathrm{g}}$
  3. $\mathrm{I}_2-\mathrm{I}_{\mathrm{g}}$
  4. $\mathrm{I}_2$

Solution

As the bridge is balanced, no current will flow through the galvanometer. Hence, the current through the $40 \Omega$ resistor will be $I_2$. .

Asked in: MHT CET 2023 (13 May Shift 1)

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