In a cyclic process, work done by the system is
- more than the heat given to the system.
- equal to the heat given to the system.
- zero.
- independent of the heat given to the system.
Solution
Cyclic process analysis begins with recognition that the system returns to its initial state. Since internal energy $U$ is a state function, $\Delta U = 0$ over any complete cycle.
The First Law of Thermodynamics $\Delta U = Q - W$ reduces to $0 = Q - W$ for cyclic processes, where $Q$ represents net heat transfer and $W$ represents net work done by the system.
This yields the fundamental relation $Q = W$ for all cyclic thermodynamic processes, indicating that net work output equals net heat input.
The correct conclusion is therefore $\boxed{B}$.
Asked in: MHT CET 2025 (20 April Shift 2)