In a conductor, if the number of conduction electrons per unit volume is $8.5 \times 10^{28} m^{- 3}$ and mean free time is $25 f s$ (femto second), it’s approximate resistivity is: $(m_{e} = 9.1 \times 10^{- 31} k g)$

Question

Aicharya · Accepted Answer

We know i = n e Av d &#8658; i = V R = V A &#961; l = E A &#961; &#961; = E A i = E A n e Av d Drift velocity can be written as v d = e E m e &#964; &#961; = E A m e n e A e E &#964; = m e n e 2 &#964; = 9.1 &#215; 1 0 - 31 8.5 &#215; 1 0 28 &#215; 1.6 &#215; 10 - 19 2 &#215; 25 &#215; 1 0 - 15 &#8776; 1.65 &#215; 1 0 - 8 &#160; &#937; &#160; m

In a conductor, if the number of conduction electrons per unit volume is 8.5 × 10 28    m -…

Solution

In a conductor, if the number of conduction electrons per unit volume is 8.5 &#215; 10 28 &#8201;&#8201; m -…

Solution

In a conductor, if the number of conduction electrons per unit volume is 8.5 × 10 28 m -…