In a common emitter amplifier, a.c. current gain is 40 and input resistance is $2 k \Omega$. The load…
In a common emitter amplifier, a.c. current gain is 40 and input resistance is $2 k \Omega$. The load resistance is given as 1 $10 \mathrm{k} \Omega$. Then the voltage gain is
52
125
178
200
Solution
For CE amplifier,
$\begin{aligned}
& \beta=40, \mathrm{R}_{\mathrm{I}}=2 \mathrm{k} \Omega, \mathrm{R}_{\mathrm{o}}=10 \mathrm{k} \Omega \\
& \therefore \quad \text { Voltage gain, } \mathrm{A}_{\mathrm{v}}=\beta\left(\frac{\mathrm{R}_{\mathrm{o}}}{\mathrm{R}_{\mathrm{I}}}\right)=40 \times \frac{10}{2} \\
& =200
\end{aligned}$