In a coil, the current changes from $-2 \mathrm{~A}$ to $+2 \mathrm{~A}$ in $0.2 \mathrm{~s}$ and induces an…
- $4 \mathrm{mH}$
- $1 \mathrm{mH}$
- $5 \mathrm{mH}$
- $2.5 \mathrm{mH}$
Solution
In magnitude form, $\begin{aligned} & \left|\operatorname{Emf}_{\text {ind }}\right|=\left|(-) L \frac{\mathrm{di}}{\mathrm{dt}}\right| \\ & \Rightarrow 0.1=\frac{(\mathrm{L})[+2-(-2)]}{0.2} \\ & \Rightarrow \mathrm{L}=\frac{0.1 \times 0.2}{4}=5 \mathrm{mH} \end{aligned}$
Asked in: JEE Main 2024 (06 Apr Shift 2)
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