In a co-axial, straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is zero

Question

Aicharya · Accepted Answer

Since the current carried by the outer and inner are equal and in opposite direction, magnetic field produced by the cylinders at a point P(distance r from central axis) is

$\Rightarrow {\vec{B}}_{outer} = \frac{μ_{o}}{4 π} i \frac{\vec{d l} \times \vec{r}}{r^{3}}$

$\Rightarrow {\vec{B}}_{inner} = - \frac{μ_{o}}{4 π} i \frac{\vec{d l} \times \vec{r}}{r^{3}}$

$\Rightarrow \vec{B} = {\vec{B}}_{outer} + {\vec{B}}_{inner} = 0$

In a co-axial, straight cable, the central conductor and the outer conductor carry equal currents in…

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