In a class of $40$ students, $25$ play cricket and $20$ play football. If every student plays at least one game, the number who play both is

Question

Aicharya · Accepted Answer

$n(A \cup B) = 40$, $n(A) + n(B) = 45$. So $n(A \cap B) = 45 - 40 = 5$.

In a class of $40$ students, $25$ play cricket and $20$ play football. If every student plays at least one…