In a circuit the current falls from 14 A to 4 A in a time 0.2 ms . If the induced emf is 150 V . then the self inductance of the circuit is

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Aicharya · Accepted Answer

$\Delta \mathrm{I}=14-4=10 \mathrm{~A}, \Delta \mathrm{t}=0.2 \mathrm{~ms}, \mathrm{e}=150 \mathrm{~V}$ $\begin{aligned} & 	herefore \mathrm{e}=\mathrm{L} \cdot \frac{\Delta \mathrm{I}}{\Delta \mathrm{t}} \Rightarrow 150=\mathrm{L} \cdot \frac{10}{0.2 	imes 10^{-3}} \ & 	herefore \mathrm{~L}=3 \mathrm{mH}\end{aligned}$

In a circuit the current falls from 14 A to 4 A in a time 0.2 ms . If the induced emf is 150 V . then the…

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