In a circle of radius $r$, a chord that subtends $90^{\circ}$ at centre has length

In a circle of radius $r$, a chord that subtends $90^{\circ}$ at centre has length
  1. $r\sqrt{2}$
  2. $r$
  3. $2r$
  4. $r/2$

Solution

$\ell = \sqrt{r^2+r^2} = r\sqrt{2}$.

Asked in: MH-SSC-9

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