In a circle of radius $r$, a chord of length $\ell$ is at distance $d$ from centre. Then

In a circle of radius $r$, a chord of length $\ell$ is at distance $d$ from centre. Then
  1. $\ell^2/4 + d^2 = r^2$
  2. $\ell + d = r$
  3. $\ell d = r^2$
  4. $\ell = 2d$

Solution

Pythagoras on the right triangle (half-chord, distance, radius).

Asked in: MH-SSC-9

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