In a circle of radius $r$, a chord at distance $d_1$ has length $\ell_1$ and another at $d_2$ has $\ell_2$.…

In a circle of radius $r$, a chord at distance $d_1$ has length $\ell_1$ and another at $d_2$ has $\ell_2$. If $\ell_1 = \ell_2$, then
  1. $d_1 = d_2$
  2. $d_1 < d_2$
  3. $d_1 > d_2$
  4. $d_1 + d_2 = r$

Solution

Equal chords $\Rightarrow$ equal distances.

Asked in: MH-SSC-9

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