Imagine that a reactor converts all the given mass into energy and that it operates at a power level of $10^{9} Watt$ . The mass of the fuel consumed $per hour$ , in the reactor, will be:
(velocity of light, $c$ is $3 \times 10^{8} m s^{- 1}$ )

Question

Imagine that a reactor converts all the given mass into energy and that it operates at a power level of

10^{9} Watt

. The mass of the fuel consumed

per hour

, in the reactor, will be:
(velocity of light,

c

is

3 \times 10^{8} m s^{- 1}

)

Aicharya · Accepted Answer

Power of reactor, P = E &#916; t = &#916; m c 2 &#916; t (From mass-energy equivalence equation) Given in the problem power level = 10 9 &#160; Watt . &#8710; m &#8710; t = P c 2 &#160; = 10 9 3 &#215; 10 8 2 &#8658; &#160; &#8710; m &#8710; t = 10 - 7 9 &#160; k g &#160; s - 1 &#160; The mass of fuel consumed per &#160; hour = 10 - 7 9 &#215; 1000&#160; g 3600 &#160; h - 1 = 4 &#215; 10 - 2&#160; g&#160; h - 1 .

Imagine that a reactor converts all the given mass into energy and that it operates at a power level of 10 9…

Solution