If ∫ cos θ 5 + 7 sin θ - 2 cos 2 θ d θ = Alog e | B ( θ ) | + C , where C is a constant of integration, then B ( θ ) A can be:

Question

If &#8747; cos &#952; 5 + 7 sin &#952; - 2 cos 2 &#952; d &#952; = Alog e | B ( &#952; ) | + C , where C is a constant of integration, then B ( &#952; ) A can be:

Aicharya · Accepted Answer

I = &#8747; cos &#952; 2 sin 2 &#952; + 7 sin &#952; + 3 d &#952; sin &#952; = t &#160;&#160; &#8658; &#160;&#160; cos &#952; d &#952; = d t = 1 2 &#8747; 1 t 2 + 7 2 t + 3 2 d t = 1 2 &#8747; 1 t + 7 4 2 - 5 4 2 d t = 1 5 ln 2 t + 1 t + 3 + c = 1 5 ln 2 sin &#952; + 1 sin &#952; + 3 + c so A = 1 5 B ( &#952; ) = 5 ( 2 sin &#952; + 1 ) sin &#952; + 3

If ∫ cos θ 5 + 7 sin θ - 2 cos 2 θ d θ = Alog e | B ( θ ) | + C , where C is…

Solution

If &#8747; cos &#952; 5 + 7 sin &#952; - 2 cos 2 &#952; d &#952; = Alog e | B ( &#952; ) | + C , where C is…

Solution

If ∫ cos θ 5 + 7 sin θ - 2 cos 2 θ d θ = Alog e | B ( θ ) | + C , where C is…