If you are provided a set of resistances, 2   Ω ,   4   Ω ,   6   Ω…

If you are provided a set of resistances, 2 Ω, 4 Ω, 6 Ω and 8 Ω. Connect these resistances to obtain an equivalent resistance of 463 Ω.
  1. 2 Ω and 6 Ω are in parallel with 4 Ω and 8 Ω in series
  2. 4 Ω and 6 Ω are in parallel with 2 Ω and 8 Ω in series
  3. 2 Ω and 4 Ω are in parallel with 6 Ω and 8 Ω in series
  4. 6 Ω and 8 Ω are in parallel with 2 Ω and 4 Ω in series

Solution

We can arrange the circuit like above now on solving we get a simplified circuit, 

here, both the resistance are connected in series then resultant resistance will be, 

Req=43 Ω+14 Ω=463 Ω, in the other case we can not get this result.

Asked in: JEE Main 2021 (26 Aug Shift 2)

Practice more Current Electricity questions on Aicharya